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HP UCMDB 9.05 Enricment Rules Question

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Hello all!

I want to make that all Ci`s with type node automatically relate with one custom type CI.

In Enricment Rules i create query that contains two ci types without relations, and i create relationship between this ci types in enricment mode.
When i`m trying to save enricment rule i have en error "Node or relationship element in query is required".
When i add relationship in query mode between ci types error disappear, but i need to add relationship betwenn cis that no have any relations, so how i can make this? Query in Enricment rules can`t put to query result two ci type instances without relations? 

 

P.S. This thread has been moved from Application Perf Mgmt (BAC / BSM) Support and News Forum to CMS and Discovery Support and News Forum. -HP Forum Moderator

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Re: HP UCMDB 9.05 Enricment Rules Question

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Hi, You need to create a Join- Relationship between the two CIT in query mode, the join-relationship defines how the two CIt must be related ( for example by an attribute values) , then you can create the relationship in enrichment mode. I hope that this suggestion will be help. Regards, Patrizia

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Re: HP UCMDB 9.05 Enricment Rules Question

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Hi, You need to create a Join- Relationship between the two CIT in query mode, the join-relationship defines how the two CIt must be related ( for example by an attribute values) , then you can create the relationship in enrichment mode. I hope that this suggestion will be help. Regards, Patrizia

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Re: HP UCMDB 9.05 Enricment Rules Question

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Hi Mastron,

 

What was the node condition that you would want to apply on your nodes? There are two challenges with your approach:

 

1) Without selecting any node condition even if the enrichment would have worked it would have inserted a relationship from each Node to each Custom CI.

2) If you are applying any node condition you would have to change it for each set of CIs, which is not a wise approach.

 

Obviously you need something common between both CITs like a attribute or some other factor and based on that you can insert the relationship.

 

Regards,

Puneet

Regards
Puneet

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