Remotely launch flow - How to get UUID?
For reasons that are too long to go into we are only now moving from HPOO 9.07 to OO 2019-07.
It is good the upgrade process I drew up around 3 years ago to go to 10.60 does not seem to have changed.
HOWEVER, we have Linux and Windows boxes which use rsFlowInvoke/JRSFlowInvoke to invoke flows.
I understand OOSH replaces that, but that seems to be based on the UUID vs /Library/My Ops Flows/Terry/TestFlow format.
Under version 10.60 the rsFlowInvoke/JRSFlowInvoke method of calling flows was still there, but depreciated (So could disappear at any point).
So now to my questions,
1) Under 2019-07 is the rsFlowInvoke/JRSFlowInvoke method of calling flows still depreciated but usaable? (I have to ask)
2) Does Rest API allow us to use a Content Pack/Path/Flow sort of paths as opposed to the UUID?
3) How do we get the UUID of a flow? (I'm assuming REST API, but worth asking the question)
Thanks in advance for any help you can provide,
Re: Remotely launch flow - How to get UUID?
It seems that there is no direct way to get UUID from the flow in the OO 10.x.
The not-so-direct way is to use the rest API:
( https://docs.microfocus.com/itom/Operations_Orchestration:2019.07/FlowLibrary )
You can get a list of all the flows in a folder with the UUID, Then you can parse the API output and filter by the flow name to get its UUID .
Or maybe you can submit a idea in Idea Exchange https://community.microfocus.com/t5/Operations-Orchestration-Idea/idb-p/OO_Idea_Exchange, to ask for a feature for OOSH to invoke a flow by its path.