Not returning Row number by using LeanFT SAPGUI Method findRowWithCellTextInColumn("text","column")

[Surjeet Chaudhary]

I am expecting row number by using  LeanFt SAPGUI sdk method findRowWithCellTextInColumn("text","column") but it's returning like "com.hp.lft.sdk.internal.sap.gui.SapGuiTableRow@20312893". 

Please help me on below code:-

Table ConditionTable=session.describe(Table.class, new TableDescription.Builder()
.type(com.hp.lft.sdk.sap.gui.ComponentType.TABLE_CONTROL).name("SAPLV69ATCTRL_KONDITIONEN").build()); 
TableRow<TableCell> intRow=ConditionTable.findRowWithCellTextInColumn("ZRFW",2);
System.out.println(intRow);

output:-com.hp.lft.sdk.internal.sap.gui.SapGuiTableRow@20312893

Thanks,

Surjeet

[Anton]

Hi Surjeet,

as you can see from the findRowWithCellTextInColumn API it returns TableRow<TableCell> and not an int (the row index).

the returned TableRow is an object representing the found row, you can get its cells using the getCells or getCell methods and then click, validate, or change the cell value (using the click\getValue\setValue methods).

LeanFT currently does not expose the row index of the found row, if you need this functionality, I would suggest to contact MicroFocus support and ask them to open an enhancement request on this matter.

Regards,

Anton 

[PascalCalovini]

Hi Anton,

do you have a hint (sourcecode) how to click() the cell? When I do that I get a runtime error: after activating the cell it returns an LFT-exception object not found.

My main topic is: how to do a doubleclick on a cell? the grid.cell.doubleclick needs int values.

Thanks for any tip

P.